Tuesday, August 25, 2009

Find Subnet n Valid IP

192.168.4.0 20 Segment

Find :
a) subnet
b) valid IP

Solution :

2^x = 20
2^5 = 32 (Subnet)
= 30 ( network(1) + broadcast(1)

8 8 8
192.168.4.0 1111 1000
5 net 3 host

xx = 8 + 8 + 8 +5
= 29 (192.168.4.0/29)


Bil. Host

2^x = 2^3
= 8 Host
= 6 (network(1) + broadcast(1)


IP Range

Network IP Range Broadcast
0 1 - 6 7 SEGMENT 1
8 9 - 14 15 SEGMENT 2
16 17 - 22 23 SEGMENT 3
24 25 - 30 31 SEGMENT 4
32 33 - 38 39 SEGMENT 5
40 41 - 46 47 SEGMENT 6
48 49 - 54 55 SEGMENT 7
56 57 - 62 63 SEGMENT 8
64 65 - 70 71 SEGMENT 9
72 73 - 78 79 SEGMENT 10
80 81 - 86 87 SEGMENT 11
88 89 - 94 95 SEGMENT 12
96 97 - 102 103 SEGMENT 13
104 105 - 110 111 SEGMENT 14
112 113 - 118 119 SEGMENT 15
120 121 - 126 127 SEGMENT 16
128 129 - 134 135 SEGMENT 17
136 137 - 142 143 SEGMENT 18
144 145 - 150 151 SEGMENT 19
152 153 - 158 159 SEGMENT 20

NA (Network Address) Segment 5
192.168.4.40

BA (Broadcast Address) Segment 5
192.168.4.47

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